John owns an engine which receives heat input from a reservoir at 600 k and loses heat to a sink at 300 k. what is the maximum possible efficiency of this engine? a. 25 percent b. 50 percent c. 75 percent d. 100 percent

D. 100 percent

Step-by-step explanation:

it is 100 percent because the reservoir is putting out 600k, but loses 300k, which would be easy to think it would be 50 percent because 300k is half of 600k, but however its peek outage is putting out 600k, therefore 600k = 600k, 100%.

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

83-45=38

38 was the other number

hope your goes well, here's a turkey

-thekoolkid1o1