Choose the product. -6 p3 (3 p2 + 5 p - 1) -18 p5 - 30 p4 + 6 p3 -18 p6 - 30 p3 - 6 p 18 p3 + 6 p2 - 30 p4 -18 p6 - 24 p3

8(-10x+3.5y-7)

8×-10x + 8×3.5y + 8×-7

-80x + 28y - 56

therefore

-80x+28y-56 is the correct answer

1

step-by-step explanation:

you are throwing one dart

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

the answers are in the images, i received 100% on this assignment. hope this !