Acar travels 1.2 miles from point a to point b. the car then turns at point b and travels 1.8 miles to point c before heading back to point a. the distance from point point c to point a is 1.6 miles. if the cars path is represented by a triangle what angle turn

Since we are given with the three sides of the triangle and asked to determine the angle, we can use the cosine law.

                              b² = a² + c² - 2ac(cosB)

Substituting the known values,

                         (1.8)² = (2.4)² + (1.6)² - 2(2.4)(1.6)(cosB)

The value of B from the equation is 48.6°.

B = 60.6 degree

Step-by-step explanation:

Side AB, c = 1.2 miles

Side BC, a = 1.8 miles

Side CA, b = 1.6 miles

Use Cosine rule to find the angle B.

Putting the values of a, b and c

B = 60.6 degree

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.

idk the answer but just put a

step-by-step explanation: