Ineed assistance as quickly as ! 1. state the slope and a point on the line y - 18 = 71. 3 ^ x + 98 h . 2. sketch a graph of the relation y + 4 = 2 ^ x - 3 h . explain the procedure used. 3. write an equation for a line that passes through the point (4,9) and has a slope of 16. 4. explain why y + 1 = 1 . 2 ^ x + 2 h and y - 5 = 1 . 2 ^ x - 3 h represent the same line, despite having different equations.

its 4 because 2 times 2 is 4, if you double the number two you get four

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.