Suppose that triangle abc is dilated to a’b’c’ by a scale factor of 1/5 with a center of dilation at the origin. what is the distance from the center of dilation to vertex a’

eveidence i thing that

step-by-step explanation:

the answer is a

step-by-step explanation:

x = 3 ± √(5+y)

hello,

as we don't know if g(x) is continue,

answer b

f(x)=2x²-8x+1=2(x²-4x+4)+1-8=2(x-2)²-7

vertex is (2,-7) ( a minimum since coefficient of x² is > 0)