What is an equation of the line containing the points (-1,5) and (3,9)

  y = x+6

Step-by-step explanation:

You can find an equation by using the 2-point form of the equation for a line:

  y = (y2 -y1)/(x2 -x1)·(x -x1) +y1

Filling in the given values, we have ...

  y = (9 -5)/(3 -(-1))·(x -(-1)) +5

  y = (4/4)(x +1) +5 . . . . simplifying a bit

  y = x +6

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

f(x) is the value of the function. b is the value of the function when x equals zero or the y-coordinate of the point where the line crosses the y-axis in the coordinate plane.

step-by-step explanation:

hope this !