At a large state university, the heights of male students who are interscholastic athletes is approximately normally distributed with a mean of 74.3 inches and a standard deviation of 3.5 inches. the heights of male students who don’t play interscholastic sports (we’ll call them “non-interscholastics”) is approximately normally distributed with a mean of 70.3 inches and a standard deviation of 3.2 inches. you select an srs of 10 interscholastic athletes and 12 non-interscholastics. what is the probability that the sample mean of non-interscholastics is greater than the sample mean of interscholastic athletes?

part 1 answer = 8

part 2 answer = 72

step-by-step explanation:

part 1 explanation = add all of the numbers, then divide by how many numbers you have. so, 200/25 = 8.

part 2 explanation = not gonna lie, this is hard to explain, so just google how to do it.

step-by-step explanation:

you divide the denominator by the numerator on both sides and if the quotients are equal then the fractions are equivalent

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

step-by-step explanation:

options