Given: circle k(o), m fh = (31x+3°) m gh = (33x+3°) m∠fhg = (28x−3°) find: m∠fgh

The measure of angle FGH is m∠FGH=48°

Step-by-step explanation:

step 1

Find the measure of arc FG in terms of x

we know that

The inscribed angle measures half that of the arc comprising

m∠FHG=(1/2)[arc FG]

substitute the given values

(28x−3°)=(1/2)[arc FG]

arc FG=(56x−6°)

step 2

Find the value of x

we know that

arc FG+arc FH+arc GH=360° > by complete circle

substitute the values

(56x−6°)+(31x+3°)+ (33x+3°)=360°

120x=360°

x=3°

step 3

Find the measure of angle m∠FGH

we know that

The inscribed angle measures half that of the arc comprising

m∠FGH=(1/2)[arc FH]

substitute the given values

m∠FGH=(1/2)[31x+3°]

m∠FGH=(1/2)[31(3)+3°]

m∠FGH=48°

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.