Can someone ? it’s algebra 2, and due tonight

B 71/8

Step-by-step explanation:

2x² - 5x = -12

2x² - 5x + 12 = 0 (EQ 1)

expand 2(x - p)² + q = 0 ,

since (x - p)² = x² - 2xp + pq,

2x² - 4xp +2p² + q = 0 (EQ 2)

compare x⁰ (just a number, without x) in EQ 1 and EQ 2.

2p² + q = 12 (EQ 3)

compare x in EQ 1 and EQ 2,

-4p = -5

p = 5/4

Substitute p=5/4 into EQ 3,

2(5/4)² + q =12

q = 12 - 2(5/4)²

q= 71/8

what do u need to know

step-by-step explanation:

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺