Find k and the roots if 3x^2+kx+4=0 and the sum of the roots is 3

Step-by-step explanation:

In the form ...

  ax^2 +bx +c = 0

the sum of the roots is -b/a. Here, that is -k/3. You want that value to be 3, so we have ...

  -k/3 = 3

  k = -9

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The solution can be found by completing the square. We choose to start by making the leading coefficient be 1.

  x^2 -3x +4/3 = 0

  (x^2 -3x +9/4) + (4/3 -9/4) = 0 . . . . . . . add and subtract (3/2)^2

  (x -3/2)^2 = 11/12 . . . . . . . . . . . . . . . . . . add 11/12, write as square

  x = 3/2 ± √(11/12) = (9±√33)/6 . . . . . . . .simplify

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step-by-step explanation:

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