Acollege-entrance exam is designed so that scores are normally distributed with a mean of 500 and a standard deviation of 100. using the eight-part symmetry of the area under a normal curve, what is the probability that a randomly chosen exam score is above 300? the probability

The probability is  0.977

Step-by-step explanation:

We know that the average is:

The standard deviation is:

The Z-score is:

We seek to find

The Z-score is:

The score of Z = -2 means that 300 is -2 standard deviations from the mean. Then by the rule of the 8 parts of the normal curve, the area that satisfies the conficion of 1 deviations from the mean has percentage of  2.35% for Z<-2

So

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic