Flight 202's arrival time is normally distributed with a mean arrival time of 10: 30 p. m. and a standard deviation of 15 minutes. use the eight-part symmetry of the area under a normal curve to find the probability that a randomly chosen arrival time is between 10: 00 p. m. and 11: 00 p. m. the probability is__

The probability is 0.953

Step-by-step explanation:

We know that the mean is:

The standard deviation is:

The Z-score is:

We seek to find

The Z-score is:

The score of Z =-2 means that 10:00 p.m. is -2 standard deviations from the mean. Then by the rule of the 8 parts of the normal curve, the area that satisfies the condition of 2 deviations from the mean has percentage of 2.35%

and

The score of Z =2 means that 11:00 p.m. is 2 standard deviations from the mean. Then by the rule of the 8 parts of the normal curve, the area that satisfies the condition of 2 deviations from the mean has percentage of 2.35%

answer are

step-by-step explanation: