Three consecutive integers have a sum of 42. find the integers. 100 clear und < < prev. question next questi

The three integers are 13,14,15

Step-by-step explanation:

Let x be the first integer

x+1 be the second integer

x+2 be the third integer

The sum of the three integers is 42

x+ (x+1) + (x+2) = 42

Combine like terms

3x+3 = 42

Subtract 3 from each side

3x+3-3 = 42-3

3x= 39

Divide by 3

3x/3 = 39/3

x = 13

x+1 = 14

x+2 = 15

The three integers are 13,14,15

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.