The school enrollment for oakwood elementary is shown in the graph. if the pattern continues, what will the school enrollment be in 2012? question 19 options: 500 525 550 575

Option B. 525 students.

Step-by-step explanation:

The school enrollment for Oakwood Elementary is shown in the graph.

The given graph is representing a linear function. So we will form the function first to calculate the enrollment in 2012.

Equation of the given line in the graph will be in the form of y = mx + c

where m is the slope and c = y- intercept

y-intercept = 300

this line passes through two ordered pairs (0, 300) and (1, 325)

Now the slope m =

m =

Therefore, equation representing the situation will be y = 25x + 300

Now we will put the value of x = year 2012 - year 2003 = 9 years

y = 25×9 + 300

y = 225 + 300

y = 525

Option B. 525 is the correct option.

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841