What are the zeros of the function? f(x)=x3+x2−6x

x = - 3, x = 0, x = 2

Step-by-step explanation:

To find the zeros equate f(x) to zero, that is

x³ + x² - 6x = 0 ← factor out x from each term

x(x² + x - 6) = 0

x(x + 3)(x - 2) = 0

Equate each factor to zero and solve for x

x = 0

x + 3 = 0 ⇒ x = - 3

x - 2 = 0 ⇒ x = 2

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step-by-step explanation:

or

step-by-step explanation:

we need to solve for 'x' the following equation:  

we have that:

⇒

⇒ ⇒

factorizing, we get that:

  ⇒

then, the solutions are: or

nothing extraneous has been found!