The diagonals of quadrilateral abcd intersect at e (2,5). abcd has vertices at a (3,7) and b (3,6). what must be the coordinates of upper c and upper d to ensure that abcd is a parallelogram?

C(1,3) and D(1,4).

Step-by-step explanation:

The given quadrilateral ABCD has vertices at A (3,7) and B (3,6). The diagonals of  this quadrilateral ABCD intersect at E (2,5).

Recall that, the diagonals of a parallelogram bisects each other.

This means that; E(2,5) is the midpoint of each diagonal.

Let C and D have coordinates C(m,n) and D(s,t)

Using the midpoint rule:

The midpoint of AC is

This implies that;

The midpoint of BD is

This implies that;

Therefore the coordinates of C are (1,3) and D(1,4).

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

c. 6tan80

step-by-step explanation: