The prism has a surface area of 202 ft2.
what would the surface area of the prism be if each dimension were tripled?
ft2
prism with a length of five feet, a width of nine feet, and a height of four feet

Old Surface Area = 202 ft^2

 New Surface Area = 1818 ft^2

  Notice we have this ratio: (new area)/(old area) = 1818/202 = 9 and how 3^2 = 9. This is no coincidence.

 The old surface area is multiplied by 3^2 = 9 to get the new surface area
. If you asked "What would the surface area of the prism be if each dimension were quadrupled?"

, then you would multiply the old surface area by 4^2 = 16 to get the new surface area  So really thats how you would solve that 

The vertex of the quadratic function is (1.5, -.75)