What is the solution set of x² + 5 x + 1 = 0 hurry im taking a test

Step-by-step explanation:

x² + 5 x + 1 = 0

note :

hello :  

the discriminat of each quadratic equation : ax²+bx+c=0 (a ≠ 0) is :

Δ = b² -4ac

1 )  Δ > 0  the equation has two reals solutions : x =  (-b±√Δ)/2a

2 ) Δ = 0 : one solution : x = -b/2a

3 ) Δ < 0 : no reals solutions

you have : a = 1   b=5  c= 1

calculate :  Δ

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.

4+3x is the answer

hope you got it