Find the values of m and b that make the following function differentiable. f(x) = {x^2, x less than or equal to 2 mx+b, x> 2} you so

In order to be differentiable everywhere, must first be continuous everywhere, which means the limits from either side as must be the same and equal to . By definition, , and

so we need to have .

For to be differentiable at , the derivative needs to be continuous at , i.e.

We then need to have

Then

use formula for the circle a=3.14

step-by-step explanation:

proofs involving isosceles triangles often require special consideration because an isosceles triangle has several distinct properties that do not apply to normal triangles.(more about triangle types) therefore, when you are trying to prove that two triangles are congruent, and one or both triangles, are isosceles you have a few theorems that you can use to make your life easier.

step-by-step explanation:

an isosceles triangle has two congruent sides and two congruent angles. the congruent angles are called the base angles and the other angle is known as the vertex angle. ∠bac and ∠bca are the base angles of the triangle picture on the left. the vertex angle is ∠abc