Afast food restaurant sells burgers, chicken sandwiches, and entree salads. if a customer buys a burger, the probability they buy french fries is 0.80. fifty percent of customers who purchase a chicken sandwich also buy fries, but only 10% of those buying an entree salad buy fries. of all customers, 65% buy a burger, 20% a chicken sandwich, the rest buy an entree salad. what proportion of customers get a burger and fries?

52%

Step-by-step explanation:

We are told that, of all customers 65% buy a burger. This would imply that the proportion of customers who buy a burger is 0.65.

Moreover, if a customer buys a burger, the probability they buy french fries is 0.80. This implies that the proportion of customers who buy fries given that they bought a burger is 0.8.

Therefore, the proportion of customers who get a burger and fries is simply the product of the two probabilities;

= 0.65*0.8

= 0.52

Therefore, 52% of all customers get a burger and fries

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

answer: $13,622.84

step-by-step explanation: check the picture for info and stats : )