Suppose f varies directly as g, and f varies inversely as h. find g when f = 12 and h = 10, if g = 198 when h = –11 and f = –6. round your answer to the nearest hundredth, if necessary. question 5 options: –360 –40 40 360

360

Step-by-step explanation:

f varies directly as g

f = kg  where k is the constant of variation

f varies inversely as h

f = kg/h

We know g = 198 when  h = –11 and f = –6.  Substituting in

-6 = k*198/(-11)

-6 =k*(-18)

Dividing each side by -18

-6/-18 = k*-18/-18

1/3 =k

Our equation is

f = 1/3 g/h

Letting  f = 12 and h = 10

12 = 1/3 g/10

Multiply each side by 10

12*10 =1/3 g/10*10

120 = 1/3 g

Multiply each side by 3

120*3 =1/3 g *3

360 =g

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1

answer: what are the following choices