Need badly. if the area of bac=15, what is the area of edf

A = 9.6 in²

Step-by-step explanation:

Since the triangles are similar, that means that their side lengths, and all lines put on respective locations, will be proportional.

1. Find the height of ∆BAC: A = 0.5 * bh --> 15 = 0.5 * 5 * h --> h₁ = 6 in.

2. Find the height of ∆EDF: 6/5 = h₂/4 --> 5h₂ = 24 --> h = 4.8 in.

3. Find the area of ∆EDF: A = 0.5 * 4.8 * 4 --> A = 9.6 in²

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

144.50

step-by-step explanation:

21.5 x 13.4=288.10 divide by 2