Urgent using the following equation, find the center and radius of the circle. you must show all work and calculations to receive credit. x2 −2x + y2 − 6y = 26 do not write out sentences, just calculations.

Center = (1,3)

Radius = 6

Step-by-step explanation:

(-2/2)^2 = 1

(-6/2)^2 = 9

x^2 -2x + 1 + y^2 -6y + 9 = 26 + 1 + 9

(x-1)^2 + (y-3)^2 =36

6^2 = 36

Center= (1,3)

Radius= 6

(1,3) is the center and the radius is 6

Step-by-step explanation:

x^2 −2x + y^2 − 6y = 26

Complete the square for the x term

(-2/2)^2 =(-1)^2= 1  so add 1 to each side

x^2 −2x +1+ y^2 − 6y = 26+1

(x-1)^2+ y^2 − 6y = 27

Complete the square for the y term

(-6/2)^2 =(-3)^2= 9  so add 9 to each side

(x-1)^2+ y^2 − 6y+9 = 27+9

(x-1)^2+ (y-3)^2 = 36

(x-1)^2+ (y-3)^2 = 6^2

This is in the form

(x-h)^2+ (y-k)^2 = r^2  where (h,k) is the center and r is the radius

(1,3) is the center and the radius is 6

38.5

step-by-step explanation:

lets say, first number = r

second number = 3r+7

total = 49

(r)+(3r+7)= 49

4r+7 = 49

4r = 42

r = 42/4

r= 10.5

3r+7 = 3(10.5)+7 = 38.5

hope this

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step-by-step explanation: