An art student wishes to create a clay sphere as part of a sculpture. if the clay’s density is approximately 88 pounds per cubic foot and the sphere’s radius is 2 feet, what is the weight of the sphere to the nearest pound? use 3.14 for pi, and enter the number only.

The weight of the sphere = 2947 pounds

Step-by-step explanation:

* Lets revise the volume of the sphere

- The volume of the sphere is 4/3 π r³, where r is the radius of

  the sphere

- Density = mass ÷ volume

- Mass is the weight and volume is the size, so density is weight

 divided through size

- Density = weight ÷ volume

* Now lets solve the problem

∵ The clay's density ≅ 88 pounds/cubic foot

∵ The radius of the sphere is 2 feet

∵ The volume of the sphere = 4/3 π r³

∴ The volume of the sphere = 4/3 π (2)³ = 32/3 π feet³

∵ Density = weight/volume ⇒ by using cross multiply

∴ Weight = density × volume

∵ Density = 88 pounds/foot³

∵ Volume = 32/3 π feet³

∵ π = 3.14

∴ The weight of the sphere = 88 × 32/3 × 3.14 = 2947 pounds

the 3rd option is right

step-by-step explanation:

1 1/7 hope i

step-by-step explanation:

8/7 = (1 * 7 + 1) / 7 = 1 + 1/7 = 1 1/7