Awater sprinkler rotates in a circular pattern witha radius of 8 feet. if the sprinkler stops 60 degrees short of completing the circular patterns, which is closest to the distance of the outer are that is not getting sprinkled with water a.4.19 ft b.8.37ft c.41.87ft d.50.24ft

B. 8.37 ft

Step-by-step explanation:

⇒This question is on circumference

⇒The water sprinkler covers a circular pattern as it moves to cover 300° and remain with 60° to cover so as to complete a single circular pattern.

⇒The remaining distance asked is the one represented by 60°

⇒Apply the formula for circumference of a circle with angle theta

  where alpha is the angle in degrees

Given that r=8ft and ∝=60°

c=3.14×2×8×60°/360°

c=8.37 ft

3+x

step-by-step explanation:

for this case we have that by definition, the surface area of a cylinder is given by:

where:

r: it is the radius of the cylinder

h: it is the height of the cylinder

we can also rewrite it as:

where:

la: it's the lateral area

ba: area of the base

option a