Permutation problem that i just do not feel like solving your cousin, who is planning her wedding, is working on the seating chart for the reception. she is trying to decide which 6 people should be seated at the table closest to the head table. she has narrowed her decision down to a list of 10 friends. if the order doesn't matter, in how many ways can she choose 6 friends from the list of 10 to sit at the table closest to the head table?

210. she has 210 ways to choose 6 friends from the list of 10 to sit at the table closest to the head table no matter the order.

This is a problem of combinations and can be solved using the equation , where n! and k! is the factorial of a number. The factorial is defined in principle as the product of all positive integers from 1 (ie, natural numbers) to n.

She has a list of 10 friends and we want to know in how many ways she can choose 6 friends.

Using the combinations equation, with n = 10 and k = 6:

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step-by-step explanation:

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step-by-step explanation: