Afamily is canoeing downstream (with the current). their speed relative to the banks of the river averages 2.75 mi/h. during the return trip, they paddle upstream (against the current), averaging 1.5 mi/h relative to the riverbank. write and solve a system of equations to find the family’s paddling speed in still water. let s equal the families paddling speed and c represent the current
a.
s + c = 2.75
s - c = 1.5
2.125 mi/h
c.
s + c = 2.75
c - s = 1.5
.60 mi/h
b.
2.75s = c
1.5s = c
1.725 mi/h
d.
2.75c = s
1.5c = s
30 mi/h

A. s=2.125 mph, c=0.625 mph

Step-by-step explanation:

Let s be the families paddling speed in still water and c be the current speed

1. A family is canoeing downstream (with the current). Their speed relative to the banks of the river averages 2.75 mi/h. Thus,

s+c=2.75

2.  During the return trip, they paddle upstream (against the current), averaging 1.5 mi/h relative to the riverbank. Thus,

s-c=1.5

3. We get the system of two equations:

Add these two equations:

Subtract these two equations:

A.

s + c = 2.75

s - c = 1.5

2.125 mi/h

Step-by-step explanation:

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17

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