Mathematics, 23.08.2019 03:00 naomicervero
The work of a student to solve a set of equations is shown:
equation a: y = 4 β 2z
equation b: 4y = 2 β 4z
step 1:
β4(y) = β4(4 β 2z) [equation a is multiplied by β4.]
4y = 2 β 4z [equation b]
step 2:
β4y = 4 β 2z [equation a in step 1 is simplified.]
4y = 2 β 4z [equation b]
step 3:
0 = 6 β 6z [equations in step 2 are added.]
step 4:
6z = 6
step 5:
z = 1
in which step did the student first make an error?
step 1
step 3
step 4
step 2
Answers: 1
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The work of a student to solve a set of equations is shown:
equation a: y = 4 β 2z
equ...
equation a: y = 4 β 2z
equ...
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