Line jk passes through points j(–3, 11) and k(1, –3). what is the equation of line jk in standard form?

7x + 2y = –1
7x + 2y = 1
14x + 4y = –1
14x + 4y = 1

For this case we must find the slope of the JK line:

Substituting the JK points we have:

So, the equation is:

We find the cut point:

Then, finally the equation is:

Manipulating algebraically:

Option B

ANSWER

EXPLANATION

The given line JK passes through points J(–3, 11) and K(1, –3)

We obtain the slope using the formula;

.The equation is given by

we have the parent function given by,

1. the function is translated 5 units to the left.

so, we get,   becomes

2. the function is translated 5 units to the right.

so, we get,   becomes

3. the function is translated 5 units upwards.

so, we get,   becomes

4. the function is translated 5 units downwards.

so, we get,   becomes

5. the function is reflected across x-axis.

so, we get,   becomes

6. the function is reflected across y-axis.

so, we get,   becomes .

step-by-step explanation:

mark brainliest.

the correct answer would be:

220 centimeters

to get this you can use the pythagorean theorem

hope this

step-by-step explanation: