Arectangular box is 4 cm ? wide, 4 cm ? tall, and 12 cm long. what is the diameter of the smallest circular opening through which the box will? fit?

The smallest box dimensions are 4 x 4 cm.

Find the diagonal and this would be the diameter of the smallest circle.

Using the Pythagorean theorem:

4^2 + 4^2 = c^2

16 + 16 = c^2

c^2 = 32

c = √32

c = 5.658 cm ( Round answer as needed.)

4.6875 pounds

step-by-step explanation:

the forst and 3rd

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