Mathematics, 13.10.2019 18:30 kaikao17801
Aparallelogram has vertices at (5, 3), (8, 4), (7, 8), and (4, 7). what is the approximate area of the parallelogram?
12 unit
13 units
17 units
27 units
and show ! will mark !
Answers: 1
![Area=2\times \frac{1}{2}[|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|]](/tpl/images/0316/4146/eba55.png)
, 
. and 
are the vertices of one of the triangles created by the diagonals.![Area=[|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|]](/tpl/images/0316/4146/e1dbc.png)
![Area=[|5(4-8)+8(8-3)+7(3-4)|]](/tpl/images/0316/4146/c300c.png)
![Area=[|-20+40-7|]](/tpl/images/0316/4146/4a997.png)
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Aparallelogram has vertices at (5, 3), (8, 4), (7, 8), and (4, 7). what is the approximate area of t...
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