equation 1: m = 8 + 2n
Mathematics, 29.12.2019 04:31 Woodlandgirl14
The work of a student to solve a set of equations is shown:
equation 1: m = 8 + 2n
equation 2: 6m = 4 + 4n
step 1: β6(m) = β6(8 + 2n) [equation 1 is multiplied by β6.]
6m = 4 + 4n [equation 2]
step 2: β6m = β48 β 12n [equation 1 in step 1 is simplified.]
6m = 4 + 4n [equation 2]
step 3: β6m + 6m = β48 β 12n + 4n [equations in step 2 are added.]
step 4: 0 = β48 β 8n
step 5: n = β6
in which step did the student first make an error?
step 3
step 5
step 4
step 2
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equation 1: m = 8 + 2n
equation 1: m = 8 + 2n
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