Easy, asap!

this project is due at 11: 30, and i have no idea what i am doing considering i was absent for a week! someone show the work and answers to all three problems before i fail this project

Number 1: x = 5

Number 2: y = 3, x = 1

Number 3: x = 40

Step-by-step explanation:

For Number 1 you have to keep in mind that quadrilaterals have an interior angle measurement of 360°.

With that in mind, all the angles must add up to 360° (duh).

(20x - 16) + (81) + (16x + 10) + (15x + 30)

20x - 16 + 81 + 16x + 10 + 15x + 30 = 360

That's a bloody mess! We should really combine like terms.

20x - 16 + 81 + 16x + 10 + 15x + 30

51x + 105 = 360

That looks a lot better, basic algebra from here, where we droppin' bois?

51x = 255

x = 5

This one's real easy.

In a parallelogram, the sides opposite from each other are equal, therefore:

2y + 2 = 4y - 4

and

x + 6 = 7x

Both are very easy to solve, here:

2y + 2 = 4y - 4

2y + 6 = 4y

6 = 2y

3 = y

Easy!

x + 6 = 7x

6 = 6x

1 = x

Are you kidding me? This is easy stuff, kid.

In a Rhombus, in case you didn't know, its diagonals (the lines connecting points diagonal to each other) are ALWAYS perpendicular to one another (intersect at 90°) which means:

2x + 10 = 90

2x = 80

x = 40

That will be all, ya boi Keith.

i need the options

step-by-step explanation: