Suppose that you ask three friends to go to the mall. each one has a 0.70 chance of saying yes. what is the probability that all three friends will say they can go to the mall with you? a. 0.027 c. 0.343 b. 0.21 d. 0.657

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Your answer would be 0.343.

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Step-by-step explanation:

In the probability questions like this one, in order to get the answer,we would use the multiplication rule.

In your questions, we are trying to find the probability of ALL of your friends going to the mall with you.

Lets make it easier for you.

Whenever in probability you can say and, you multiply.

This means that you would try to find if friend 1 and friend 2 and friend 3 will say yes.

That's the same as saying friend 1's probability × friend 2's  probability × friend 3's  probability

We know that each friend has a 0.70 chance of saying yes.

Using the multiplication rule, we would just multiply 0.7 three times.

When you multiply, you should get 0.343.

There is a 0.343 chance of ALL your friends saying yes to go to the mall with you.

0.343 would be your FINAL answer.

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intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

both the histogram and the stem and leaf plot will visually show how many shoppers were of various ages within each range of data.   the histogram does not give us the specific ages of these shoppers unlike the stem and leaf plot.a histogram does not give us a true range of the data because we do not know exactly how old the shoppers were. a stem and leaf plot will give exact ages, so we can determine the exact range along with all measures of center and the others measures of center.   with the histogram, we cannot find any of these.

step-by-step explanation: