Adiameter of a circle has end points p(-10,-2) and q(4,6)
a. find the center of the circle
b. find the radius. if your answer is not an integer express it in a radical form.
c. write and equation for the circle
giving brainliest

Step-by-step explanation:

A]

The center is the average values of the 2 endpoints (which is also the diameter).

x:(-10 + 4)/2 = -6/2 = -3

y:(-2 + 6)/2 = 4/2 = 2

Center(-3,2)

B]

The radius is the distance from the center to one of the end points.

r^2 = (-3 - 4)^2 + (2 - 6)^2

r^2 = (-7)^2 + (-4)^2

r^2 = 49 + 16

r^2 = 65

r = sqrt(65)

C]

(x + 3)^2 + (y - 2)^2 = 65

Graph

The graph has been included so that you can see that the center I have calculated is between (-10,-2) and (4,6)

Further, it shows the the circle goes the two end points of the diameter.

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