What is the value of the expression “eight more than three times the difference of four and a number” when n = 3?

 11

Step-by-step explanation:

Let the number is n

Then as per statement of the question

"Eight more than three times the difference of four and a number"

Expression will be [3(4-n)+8]

Now for n = 3

Value of the expression will be [3(4 - 3 ) +8]

                    = [ 3 × 1 + 8 ]

                   = 11

i am unable to solve this problem

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)