Divide the polynomial x^3+x^2-2x+3 by (x-1)

x² + 2x + (3 / (x − 1))

Step-by-step explanation:

Start by setting up the division:

x − 1 | x³ + x² − 2x + 3

Start with the first term, x³.  Divided by x, that's x².  So:

x²

x − 1 | x³ + x² − 2x + 3

Multiply x − 1 by x², subtract the result, and drop down the next term:

x²

x − 1 | x³ + x² − 2x + 3

-(x³ − x²)

2x² − 2x

Repeat the process over again.  First term is 2x².  Divided by x is 2x.  So:

x² + 2x __

x − 1 | x³ + x² − 2x + 3

-(x³ − x²)

2x² − 2x

Multiply, subtract the result, and drop down the next term:

x² + 2x __

x − 1 | x³ + x² − 2x + 3

-(x³ − x²)

2x² − 2x

-(2x² − 2x)

3

x doesn't divide into 3, so that's the remainder.

Therefore, the answer is:

x² + 2x + (3 / (x − 1))

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step-by-step explanation:

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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