Afield with an area of 2880 ft2 has the shape of a rectangle, whose length is 12 ft larger than its width. find the dimensions of this field.

 The dimensions of the field are

width = 40 ft and length = 60 ft.  

Step-by-step explanation:  Given that a field with an area of 2880 ft² has the shape of a rectangle with length 12 ft larger than the width.

We are to find the dimensions of the field.

Let w ft be the width of the given rectangular field.

Then, the length of the field will be (w + 12) ft.

According to the given information, we have

Since the measure of a side of a rectangle cannot be negative, so w = 48.

This implies that

length of the field = w + 12 = 48 + 12 = 60 ft.

Thus, the dimensions of the field are

width = 40 ft and length = 60 ft.  

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.