Suppose abcd is a rhombus and that the bisector of ∠abd meets
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at point k. prove that m∠akb = 3m∠abk.
m∠akb = m∠kbd + m∠
by reason
find the angle that missing angle so that angle kbd and that angle will equal angle akb.
explain

Step-by-step explanation:

Proof:

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Proof is always in the eye of the beholder, and the details depend on the supporting theorems and postulates you're allowed to invoke. The basic idea is that you have cut a vertex angle in half twice, and you're trying to show that the smallest part to the rest of it has the ratio 1 : 3.

repeat the question

step-by-step explanation:

if the pizza is divided equally into 2 equal halves then you would get

πr^2/2

where r is the radius of the pizza.

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