What can you say about the yvalues of the two functions f(x)=3^x-3 and g(x)=7x^2-3 answer

Step-by-step explanation:

This question is too general.  We can take a look at the behaviors of the two different graphs:

f(x)=3^x-3 is an exponential function whose y-intercept is (0, -2).  Note that 3^0 = 1.  To draw this function, we'd drawn f(x)=3^x first and then translate the whole graph down by 3 units.  The graph appears in Quadrants III, IV and I, in that order.

g(x)=7x^2-3 is not an exponential function, but rather a quadratic whose graph is a parabola.  Here the parabolic graph opens up.  Its y-intercept is (0, -3).  This graph will intersect that of f(x)=3^x-3 in two places.

A:  False.  It is g that has minimum y value of -3.  The minimum y value of f is -2.

B:  The smallest y value f can have is just above y = -2.  y = -2 is the horizontal asymptote for this function.  The smallest y value g can have is -3.  So B is False.

C:  True.  g has the smallest possible y-value; it is -3.

D:  True.  The min. y-value of g is -3.

∞ this is your sign