Acan company makes a cylindrical can that has a radius of 6 cm and a height of 10 cm. one of the company’s clients needs a cylindrical can that has the same volume but is 15 cm tall. what must the new radius be to meet the client’s need? round to the nearest tenth of a centimeter.

2.7 cm
4.9 cm
7.3 cm
24.0 cm

  4.9 cm

Step-by-step explanation:

The original can has a volume of ...

  V = πr²h = π(6 cm)²(10 cm) = 360π cm³

The new can will have the same volume, but a different height:

  360π cm³ = πr²(15 cm)

  24 cm² = r² . . . . . divide by 15π cm

  r = √24 cm ≈ 4.9 cm . . . . . take the square root

The new radius must be about 4.9 cm.

answer: i wpould go with c

step-by-step explanation:

it is a secret for it not to be compromised sorry

step-by-step explanation: