Let f(x)=x2−3x−4 .

what is the average rate of change from x = 7 to x = 10?

The average rate of change from x= 7 to x=10 is 14

Step-by-step explanation:

We can use the slope formula to find the average rate of change

Now, we are given f(x) = x^2-3x-4 and x=7 to x=10

Our formula can be rewritten as:

finding f(10) = (10)^2 -3(10) -4

                   = 100 -30 -4

                   = 66

and f(7) = (7)^2 -3(7) -4

            = 49-21-4

            = 24

Now finding m:

m= 66 - 24 / 10-7

m= 42/3

m= 14

So, the average rate of change from x= 7 to x=10 is 14.

ANSWER

EXPLANATION

The given function is

The average rate of change from x=7 to x=10 is given by;

The average rate of change now becomes:

answer: this doesnt make any sense especially the photo.

step-by-step explanation:

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}