If the zeros of the quadratic equation x^2+25=0 are +-5 (plus-minus 5), what is the correct factored form?

(x+5)(x-5)=0
(x+5i)(x-5i)=0
(x+12.5i)(x-12.5i)=0
(x+12.5)(x-12.5)=0

ANSWER

EXPLANATION

The given function is

The zeros of this function are;

Or

Hence the factored form is:

If the equation were:

Then the factored form is

5/6

step-by-step explanation:

if i remember correctly with perpendicular stuff you just take away the negative

answer: 590

step-by-step explanation: