What are the zeros of the function f(x)= x^2-x-12/ x^2+x-12

x=-3 ;       x= 4

Step-by-step explanation:

zeros of the function are the value of x at which the function becomes zero. Or graphically when the graph line crosses the x-axis those values of x are the zeros of the function.

Finding zeros of given function f(x)= x^2-x-12/ x^2+x-12 by substituting f(x)=0

0=  x^2-x-12/ x^2+x-12

0= (x+3)(x-4)/(x-3)(x+4)

(x+3)(x-4)=0

(x+3)=0  ; (x-4)=0

x=-3 ;       x= 4

the zeros of the function f(x)= x^2-x-12/ x^2+x-12 are at point x=-3 and x= 4 !

the answer is 0.000652422

but if you ment to ask what is 6131 divided by 4, it is 1532.75.

step-by-step explanation:

answer: the answer is b. i think hope i got it correct

step-by-step explanation: