Find the surface area of the cylinder to the nearest whole number. the figure is not drawn to scale

Option A is correct that is Surface Area of the Cylinder is 1659 in.²

Step-by-step explanation:

Given:

Radius of the Cylinder , r = 11 in.

Height of the Cylinder , h = 13 in.

We have to find the Surface Area of Cylinder to the nearest Whole number.

We know that,

Surface Area of the Cylinder = 2πr(r+h)

                                                 = 2 × 22/7 × 11 ( 11 + 13 )

                                                 = 2 × 22/7 × 11 × 24

                                                 = 1659.42 in.²

                                                 = 1659 in.²  (nearest whole number)

Therefore, Option A is correct that is Surface Area of the Cylinder is 1659 in.²

my answer is$ 12

step-by-step explanation:

because 15 -2=12

geometry: triangles

solvers

lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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