What is the solution of this system of linear equations? 3y=3/2x+6 1/2y-1/4x=3.

No solution

Step-by-step explanation:

Please, separate equations with a comma, or the word "and," or a semicolon.

Next, determine the LCD and multiply both equations by it, so as to elimiinate the fractional coefficients.

3y=3/2x+6 1/2y-1/4x=3

should be written as the system

   3y=(3/2)x+6         Use parentheses around the fraction for clarity

(1/2)y-(1/4)x=3            Same:  use parentheses

The LCDs here are 2 (for the first equation) and 4 (for the second equation).  Multiply the first equation by 2 to eliminate the fractions:

   3y=(3/2)x+6         →   6y = 3x + 12, and

4[ (1/2)y-(1/4)x=3 ]     →   2y  -  x   = 12

Let's use the substitution method to solve this system.  Solve the 2nd equation for x, obtaining x = 2y - 12.  Substitute 2y - 12 for x in the 1st equation 6y = 3x + 12:

6y = 3(2y - 12) + 12, or

6y = 6y - 36 + 12

This reduces to 0 = -24, which is never true.  Thus,

this system has NO solution.

answer: i believe it’s 245.04

step-by-step explanation:

the data of the detroit pistons in numerical order from least to greatest is 0.30, 0.37, 0.55, 0.62, 0.69, 0.72, 0.73, 0.75, 0.77, 0.78, 0.80, 0.81, 0.81, 0.83, 0.84, 0.89

the data of the miami heat in numerical order from least to greatest is 0.50, 0.50, 0.56, 0.57, 0.67, 0.72, 0.72, 0.72, 0.75, 0.75, 0.76, 0.81, 0.82, 0.90, 1.00, 1.00

the detroit pistons median : 1.52

the miami heat median: 1.47

the iqr of this data is 0.05