100+ points

what is the length of the base of an isosceles triangle if the center of the inscribed circle divides the altitude to the base into the ratio of 12: 5 (from the vertex to the base), and the length of a leg is 60 cm?

Calculate half the base by multiplying the length of a side ( 60 cm) by the fraction of the ratio from the base to the vertex ( 5/12).

Then multiply that by 2 for the width of the base.

60 x 5/12 = 300/12 = 25 cm.

Full width = 25 x 2 = 50 cm.

a = 3.14

b = 18

c = 18/5 or 3.6 or 3 3/5

step-by-step explanation:

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm