Ytterbium decays 50% every 4.2 days. how much of an 80g sample would be left after 54.6 days? use exponential decay formula.
a. 67 g
b. 53,211.33 g
c.41.76 g
d. 9.80 g
e. 0.12 g

Option E

Step-by-step explanation:

The exponential decay formula is:

Where p is the initial amount of Ytterbium

r is the rate of decrease

C(t) is the amount of Ytterbium in grams as a function of time

t is the time in days

In this problem:

t is the time in units of 4.2 days

Then

We want to calculate the amount of Ytterbium in 54.6 days.

Then as t is the time in units of 4.2 days

Finally

step-by-step explanation:

from the graph attached below:

domain of graph is the value of x for which the given function profit function p(x) is defined.

(a) the domain represents the number of years for which the outlet will earn a profit.

range of profit function defines the lowest to highest value of profit earned.

(b) the range of this function is (0 , 160 ). for this function, the range represents the outlet's profit earned.