Write the product of the monomials (8x6y)2 and (x3y4).

The product of the monomials is 2304

Step-by-step explanation:

* Lets explain how to solve the problem

- We need to find the product of the monomials (8x 6y)² and

- At first lets solve the power of the first monomial

- Because the power 2 is on the bracket then each element inside the

  bracket will take power 2

∵ (8x 6y)² = (8)²(x)²(6)²(y)²

∵ (8)² = 64

∵ (x)² = x²

∵ (6)² = 36

∵ (y)² = y²

∴ (8x 6y)² = [64x² × 36y²]

∵ 64 × 36 = 2304 x²y²

∴ The first monomial is 2304 x²y²

∵ The first monomial is 2304 x²y²

∵ The second monomial is

- Lets find their product

- Remember in multiplication if two terms have same bases then we

  will add their powers

∵ [2304 x²y²] × [ ] =

   2304 [ ] [ ]

∵ = =

∵ = =

∴ [2304 x²y²] × [ ] = 2304

The product of the monomials is 2304

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !

2/3x + 7 = 29

step-by-step explanation:

two thirds = 2/3

plus a number = x

at least 29 = 29

there for you should get 2/3x + 7 = 29