Me. i'm so desperate not even my group chat is

5 between Martin's place and the school

Step-by-step explanation:

I don't know if you can draw a diagram from by directions, but you can try. It will help you to see the problem.

Draw

Draw a line that looks like this on your paper.

<:

school         X        Martin's place

Now draw a line going upwards from the arrow head.

∧                 Haley's place.

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<:

school       x      Martin's place

Label the distance from the school to Haley's place as 12

I can't draw a line between martin's place and Haley's but you can. Label it as 13

So the givens are

c = distance between Haley's place and Martin's = 13

b= distance from the school to Haley's is 12

a = ? Distance from Martin't and the school = x

Formula

c^2 = a^2 + b^2

Solution

13^2 = 12^2 + a^2

169 = 144 + a^2          Subtract 144 from both sides.

169 - 144 = 144 - 144 + a^2

25 = a^2

sqrt(25) = sqrt(a^2)

a = 5              

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.